Question

When the bulb of standard gas thermometer is placed in melting ice, the pressure recorded is 83cm of Hg
and when immersed in boiling water, it is 113 cm of Hg. When the bulb is placed in another boiling
liquid, the pressure recorded is 143 cm of Hg. The boiling point of the liquid is​

Answer 1

Answer:

Boiling point of the liquid is 200 degree C

Explanation:

As we know that pressure temperature is linear relation so we have

$P = kT + c$

now we have

T = 0 then P = 83 cm of Hg

so we have

$c = 83 cm$

$P = kT + 83$

at T = 100 degree the pressure is P = 113 cm of Hg

$113 = k(100) + 83$

$k = 0.3$

$P = 0.3T + 83$

Now when P = 143 cm of Hg

$143 = 0.3T + 83$

$T = 200$

#Learn

Topic : Pressure temperature relation

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Answer 2

Answer:

200℃

Explanation: