Question

when the concentration of the reactant is increased 16 times the rate becomes 2 times. find order

Answer 1

let rate eqn be

$r = k( {a}^{x} ) \\ 2r = k(16a) {}^{x} \\ \\ divide \\ \\ \frac{1}{2} = \frac{1}{ {16}^{x} } \\ x = 4$

order =4

mark as brainliest if helped