Question

When the current in the coil changes from 8 ampere to ampere in 3 into 10 to the power minus 2 seconds the emf induced in the coil is 2 volt the self inductance of the coil in milli henry is?

Answer 1

The self-inductance will be 30 mH

Explanation:

When magnetic field changes through a inductive coil emf is induced. The formula for that emf is given as  

E = L di/dt  

It is given that E = 2 and current changes from 8A to 6A in 3 into 10 power minus 2 seconds. By Putting these values in above equation, we get,

L = 30 mH