When the denominator of 1 by 2+root 5 is rationlized, It becomes root k by 10
find K .
Answers
Answer:
Purplemath
On the previous page, all the fractions containing radicals (or radicals containing fractions) had denominators that cancelled off or else simplified to whole numbers. What if we get an expression where the denominator insists on staying messy?
Simplify: \mathbf{\color{green}{\sqrt{\dfrac{25}{3}\,}}}
3
25
The numerator contains a perfect square, so I can simplify this:
\sqrt{\dfrac{25}{3}\,} = \dfrac{\sqrt{25\,}}{\sqrt{3\,}}
3
25
=
3
25
= \dfrac{\sqrt{5\times 5\,}}{\sqrt{3\,}} = \dfrac{5}{\sqrt{3\,}}=
3
5×5
=
3
5
Step-by-step explanation:
Purplemath
On the previous page, all the fractions containing radicals (or radicals containing fractions) had denominators that cancelled off or else simplified to whole numbers. What if we get an expression where the denominator insists on staying messy?
Simplify: \mathbf{\color{green}{\sqrt{\dfrac{25}{3}\,}}}
3
25
The numerator contains a perfect square, so I can simplify this:
\sqrt{\dfrac{25}{3}\,} = \dfrac{\sqrt{25\,}}{\sqrt{3\,}}
3
25
=
3
25
= \dfrac{\sqrt{5\times 5\,}}{\sqrt{3\,}} = \dfrac{5}{\sqrt{3\,}}=
3
5×5
=
3
5