when the denominator of 3/√5is rationa untillized , it become 3k/5
Find k
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When we rationalise the denominator, the value remains equal to the number before multiplying the rationalising factor.
∴ 3/√5 = 3k/5
⇒ (3√5)/(√5 × √5) = 3k/5
(Do not multiply √5 in the RHS as √5 in the denominator and numerator in the LHS will make it as it is.)
⇒ 3√5/5 = 3k/5
⇒ 3k = 3√5
⇒ k = √5.
∴ The value of k is (√5).
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