when the diameter of a wire is double,its resistence become
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The resistance of the wire is R=4ρL ∕ (πd²). Now if the diameter is doubled then the new resistance is R'=4ρL∕(π(2d)²) =4ρL∕(4πd²) =0.25R. Hence we see that the resistance of the wire becomes 25% of original resistance.
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