Question

when the digit of two-digit numbers are reversed,. the no. increase by 27 , the sum of such two digit number is?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

22 × ten's face value + 33

Step-by-step explanation:

(10x+y)+27=10y+x

27=10y+x-10x-y

27=9y-9x

27=9(y-x)

y-x=3

y=3+x

10x+y=10x+3+x=11x+3

10y+x=10(3+x)+x=11x+30

so,

addition of both will be...

11x+3+11x+30

=22x+33

VERIFYING....

If x=2, then y=5

25+52=77.....(1)

22×2+33=44+33=77...(2)

(1) and (2) are same