Question

when the digits of a two digit number are interchanged the number after the number obtained is more than the original number by 36 if the sum of the digits of the original number is 12 what is the original number

Answer 1

let ten's digit=y
let one's digit=x
number=10y+x
ATQ====
X+Y=12....................(1)
AND,
10Y+X+36=10X+Y
10Y-Y+36+X-10X=0(transporting)
9Y-9X+36=0(taking 9 as common)
-X+Y=-4....................(2)
ADDING 1 AND 2.......
......X eliminates and we get..
2Y=8
Y=4
PUT VALUE OF Y IN EQ.1
X=12-4
X=8

NUMBER=10Y+X
=10×4+8
=48


Hence number is 48..



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