Question

when the digits of a two digit number are interchanged the number obtained is more than the original number by 36 if the sum of the digits of the original number is 12
what is the original number

Answer 1

here is the answer hope it will help you mark as brainliest plezz

Answer 2

Answer:

so the original no. is 48

Step-by-step explanation:

let the tens place digit no. be x

and the ones place digit no. be y

then the original no. will=10x+y

the interchanged number=10y+x

according to the question,

x+y=12----------1

10x+y+36=10y+x------------2

from 1 we get the value of x ie

x=12-y

now come to the second equation

10x+y+36=10y+x

=>10x-x-10y+y=-36

=>9x-9y=-36

=>9y-9x=36

=>9(y-x)=36

=>y-x=36/9

=>y-x=4

now we will put the value of x here

=>y-(12-y)=4

=>y-12+y=4

=>2y-12=4

=>2y=4+12

=>2y=16

=>y=8

so the units digit is 8

the tens place digit(x)=12-ones place digit

=>x=12-8

=>x=4

so the original no. is 48