Question

When the digits of the number interchanged
Then 7 times of the original number = 4 times of the reverse number. if the sum
of the digits of the number its 3 then ,find the original number​

Answer 1

Answer:

Given sum of the digits is 3

Let the digits in ones place be x

Hence the digit in tens place is (3–x)

The original number =10(3–x)+x=30–9x

Number formed by reversing the digits =10x+(3–x)=9x+12

Given that number formed by reversing the digits is 54 greater than the original number.

⇒9x+12=(30–9x)+54=84–9x

⇒18x=84–12=72

∴x=4

The original number =30–9x=30–4×4=30−16=14

please mark me as the brainliest...