Question

When the digits of two-digit number are the reversed, the number increases by 138.5,the number of such two-digit number is -

Answer 1

Step-by-step explanation:

Let the digits of the number be x and y.

So we have

10*y + x  - (10*x + y) = 54

=> 10y + x – 10x – y = 54

=> 9y – 9x = 54

=> y – x = 54 / 9 = 6

=> y...

Answer 2

Answer:

The possible set digits can be: {1, 16} or {2, 17} or {3, 18} or {4, 19} or {5, 20} or {6, 21} or {7, 22}.

Step-by-step explanation:

Lets assume the numbers of the two digit number are a and b.

So, the number will be = (10a + b)

Now if the number is reversed, then the a will replace b and b will replace a. So the new reversed number will be = (10b + a)

Now (10b + a) > (10a + b)  [according to the given condition]

and (10b + a) - (10a + b) = 138.5

       10b + a - 10a - b = 138.5

       9b - 9a = 138.5

       9 (b - a) = 138.5

         b - a = 15

         b = 15 + a

• The possible set digits can be: {1, 16} or {2, 17} or {3, 18} or {4, 19} or {5, 20} or {6, 21} or {7, 22}.

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