Question

when the digits of two digits number are reversed the number increase by 27 the sum of such two digit number is​

Answer 1

You do have to send it over and see what it says about the number and the number number is on my account and send me a text that is number two and send me a message or call

Answer 2

Answer:

Sum of two digit is odd number, such that sum is greater than equal to 5 and less than equal to 15

Step-by-step explanation:

Let the unit digit of two digit number be x

Let the ten's digit of two digit number be y

Thus, the number = 10y + x

Reverse Number = 10x + y

Also, Given that when digits are reversed, the number increase by 27

Thus, we get

10x + y = 10y + x + 27

(10x - x) + (y - 10y) = 27

9x - 9y = 27

x - y = 3

x = y + 3

We need to find , two digits such that digit at unit place is 3 more than digit at ten's place

possible values of x and y are

x = 3, y = 0

x = 4, y = 1

x = 5, y = 2

x = 6, y = 3

x = 7, y = 4

x = 8, y = 5

x = 9, y = 6

Now, checking to find which combination is the possible answer

When x = 3, y = 0

Digit = 03 - Its is not a two digit number, hence this is not possible

When x = 4, y = 1

Digit = 14

Reverse = 41

Now,14 + 27 = 41

Sum = 1 + 4 = 5

When x = 5, y = 2

Digit = 25

Reverse = 52

Now,25 + 27 = 52

Sum = 5 + 2 = 7

When x = 6, y = 3

Digit = 36

Reverse = 63

Now,36 + 27 = 63

Sum = 6 + 3 = 9

When x = 7, y = 4

Digit = 47

Reverse = 74

Now,47 + 27 = 74

Sum = 7 + 4 = 11

When x = 8, y = 5

Digit = 58

Reverse = 85

Now, 58 + 27 = 85

Sum = 8 + 5 = 13

When x = 9, y = 6

Digit = 69

Reverse = 96

Now,69 + 27 = 96

Sum = 6 + 9 = 15