when the displacement is 0.04.
A block weighing 4.0 kg extends a spring by 0.16 m from its un-
stretched position. The block is removed and a 0.50 kg body is hung
from same spring. If the spring is now stretched and then released,
what is its period of vibration?
(T = 0.28 s)
Answers
Answered by
0
Answer:
I don't understand this question
Answered by
0
Answer:
The spring constant can be found out by
k=
0.16
4
kg/m=
0.16
40
N/m=250N/m.
Time period T is given by
T=2π
k
m
=2×3.14×
250
0.5
=0.283s
Option C is correct.
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