Physics, asked by arzhussainkorai, 1 month ago

when the displacement is 0.04.
A block weighing 4.0 kg extends a spring by 0.16 m from its un-
stretched position. The block is removed and a 0.50 kg body is hung
from same spring. If the spring is now stretched and then released,
what is its period of vibration?
(T = 0.28 s)

Answers

Answered by dhanajidamame9995
0

Answer:

I don't understand this question

Answered by adityachauhan91962
0

Answer:

The spring constant can be found out by

k=

0.16

4

kg/m=

0.16

40

N/m=250N/m.

Time period T is given by

T=2π

k

m

=2×3.14×

250

0.5

=0.283s

Option C is correct.

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