When the distance between two charged particles is made one-
third, the force between them becomes :
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Answer: force increases by 9 times
Explanation: F=Gm1m2/r^2 ('^'means raised by power)
if distance is reduced to 1/3
then ,
Gm1m2/[(1/3)R]^2
Gm1m2/(1/9)R^2
9Gm1m2/R^2 [reciprocaled 1/9]
9F [F=Gm1m2/R^2]
so, force becomes 9 times greater
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