When the distance between two charged particles is made one fourth the force between them becomes?
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we know that force between two charges is
F =k.(q1 x q2 )/r^2
ATQ,
distance is 1/4 of force,
hence, distance is 1/4 x k.(q1 x q2 )/r^2.
F =k.(q1 x q2 )/r^2
ATQ,
distance is 1/4 of force,
hence, distance is 1/4 x k.(q1 x q2 )/r^2.
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