Question

When the electrostatic force between these two identical charges is 100 N and are separated by a distance of 0.1 m. Determine the magnitude of the two identical charges.
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Answer 1

Answer:

Two equal charges are placed at a distance of 0.1m if the force between them is 100N, the amount of charge is $10.4*10^{-6}C$

Explanation:

• The force acting between stationary charges is called electrostatic force

• The coulomb's law gives the magnitude of the force as

        $F=\frac{Kq_{1} q_{2} }{r^{2} }$

        where  $K=9*10^{9}$

        $q_{1} , q_{2}$ - the charges

        $r$- the distance between the charges

From the question, we have given that

let the charge be $q$

the distance between the charges $r=0.1m$

the amount of force $F=100N$

put  the given values in the equation for force

$100=\frac{9*10^{9}*q*q }{0.1^{2} }$

⇒

$1=9*10^{9}*q^{2} \\q^{2}=0.11*10^{-9}\\q=10.4*10^{-6} C$