Physics, asked by krishnamaharana1313, 11 months ago

When the heating in coil b dissipates 33.3w of power, the potential difference v across coil given by

Answers

Answered by Anonymous
10

Answer:

Liquid enters the tube at a constant temperature of 19.5 °C and leaves the tube at

a temperature of 25.5 °C. The mass of liquid flowing through the tube per unit time is m.

Electrical power P is dissipated in the heating coil.

The student changes m and adjusts P until the final temperature of the liquid leaving the tube is 25.5 °C.

The data shown in Fig. 3.2 are obtained.

m / g s-1 P/ W

1.11 33.3

1.58 44.9

Answered by itzJitesh
0

Answer:

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