When the integer n is divided by 8, the remainder is 3. what is the remainder if 6n is divided by 8?
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Answered by
4
Heya User,
Modular Arithmetic ^_^
--> Euclid's lemma holds a proper claim here.. ^_^
--> n = 8k + 3 --> [ By Euclid's lemma ]
--> 6n = 6 ( 8k + 3 )
= 48k + 18
--> 6n = 8 [ 6k + 2 ] + 2
Hence, 6n = 8a + 2 √√
This implies that the remainder on dividing 6n with 8 is '2'.
Modular Arithmetic ^_^
--> Euclid's lemma holds a proper claim here.. ^_^
--> n = 8k + 3 --> [ By Euclid's lemma ]
--> 6n = 6 ( 8k + 3 )
= 48k + 18
--> 6n = 8 [ 6k + 2 ] + 2
Hence, 6n = 8a + 2 √√
This implies that the remainder on dividing 6n with 8 is '2'.
Answered by
3
Given,
when the integer n is divided by 8 then the remainder is 3.
To Find,
the remainder if 6n is divided by 8.
Solution,
when n is divided by 8, we get
n = 8q + 3 (here, 3 is remainder) (1)
now, multiply 6 on both sides
6n = 48q + 18
6n = 48q + 16 + 2
6n = 8(6q + 2) + 2
6m = 8m + 2 ( where, m = 6q + 2)
Hence the remainder on dividing 6n by 8 is 2.
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