when the length of each side of a square was increased by 10cm.its area becomes 36cm².what was the length of a side of the original square
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(X+10)^2=36
solve by this statement ,let orgnal side of square be x
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Step-by-step explanation:
let the length of the square be x+10cm,
Length=x+10cm
Area of square =36cm square
we know that,
Area of square =l square or l×l
36=(x+10)^2
or, root under 36=x+10
or, 6=x+10
or, 6-10=x
or, x= - 4cm
Now, length of square =x+10
(putting the value of x= - 4 )
Length of square = - 4+10
= 6cm
Hence, the length of a side of the original square is 6cm
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