Question

When the length of simple pendulum is doubled the ratio of the new frequency to the old frequency is
​

Answer 1

The frequency of simple pendulum is given by;

=12‾‾√
f
=
1
2
π
g
l

Here,

g= Local acceleration due to gravity. You can say it is effective acceleration. ie. in case of accelerating object.

l= effective length. Its the length from point of suspension to the CG of bob.

When length is doubled.

′=122‾‾√
f
′
=
1
2
π
g
2
l

′=12‾‾√
f
′
f
=
1
2

′=12√
f
′
=
1
2
f
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