When the mass is halved and the velocity is doubled, the kinetic energy of the object?
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Answer:
Let, mass = m,
m, speed = v
v KE1= (1/2)mv²
now,
- mass= m/2,
- mass= m/2, speed= 2v
mass= m/2, speed= 2v KE2 = (1/2) × (m/2) ×(2v)²
=mv² = 2KE1,
i.e., double of initial energy.
Answer: Expl: New KE = 1/2.
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