Question

when the mass of the object is doubled and the velocity is halfed than. What well be tha change of its K.E ​

Answer 1

Explanation:

$\huge{\bold{\green{\underline{\underline{\mathcal{Answer}}}}}}$

KE becomes also half

because...

if mass is doubled and velocity is halved

m' = 2m

v'= v/2

KE' = 1/2 m'v'²

KE' = 1/2 * 2m * (v/2)²

$= \frac{1}{2} \times 2m \times \frac{ {v}^{2} }{4}$

$= \frac{1}{2} \times m \times \frac{ {v}^{2} }{2}$

$= \frac{1}{2} \times \frac{m {v}^{2} }{2}$

$= \frac{1}{2} ke \: \: (as \: \frac{m {v}^{2} }{2} = k.e)$

so... the answer will be

KE' = 1/2 KE

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