Physics, asked by Kriti7418, 2 months ago

When the Momentum of a body decreases 10 percent, its K.E. decreases by
(a.) 20 percent
(b.) 40 percent
(c.) 36 percent
(d.) none of these

Answer plz....​

Answers

Answered by mohit810275133
1

Explanation:

HEY MATE ........

 \frac{ {p}^{2} }{2m}  = k.e \\  \\ p1 = 0.9p \\  \\ k.e.1 =  \frac{ {p1}^{2} }{2m}  \\  \\ \implies( {0.9}^{2} ) \frac{ {p}^{2} }{2m}  \\  \\ \implies0.81 \: k.e \\  \\ so \: k.e \: decreased \: by \: 19\% \:  \:  \\  \\ k.e = kinetic \: energy \:  \\  \\  \\  \\ so \: the \: boll \: has \: both \: the \: k.e \: and \: p.e

HOPE IT HELPS YOU

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