Question

When the momentum of body is increased by three times its k. E becomes

Answer 1

here's the answer:-

Relationship between kinetic energy and momentum is like:-

k.E= P²/ m

p= (momentum)

m= (mass)

by keeping mass constant we have:-

k.E= p²

k.E= (3)²

K.E= 9 times☺

Answer 2

The new kinetic energy becomes 9 times of the initial kinetic energy.

Explanation:

The relation between the momentum and the kinetic energy of an object is given by :

$K=\dfrac{p^2}{2m}$

Where

p is the momentum

m is the mass

If the momentum of body is increased by three times, p' = 3p

New kinetic energy will be,

$K'=\dfrac{p'^2}{2m}$

$K'=\dfrac{(3p)^2}{2m}$

$K'=9\times \dfrac{p^2}{2m}$

$K'=9\times K$

So, the new kinetic energy becomes 9 times of the initial kinetic energy. Hence, this is the required solution.

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When the momentum of body is increased by three times its k. E becomes ?

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