When the number of turns in a coil is doubled without any change in the length of the coil, its self inductance becomes(a) Four times(b)Doubled
(c) Halved(d) Unchanged
Answers
Answered by
28
answer : option (a) four times
explanation : we know, self inductance of coil or solenoid is given by
L = μ₀n²A/l
where μ is permeability of medium, n is number of turns of a coil, A is cross sectional area of coil and l is length of coil.
if A , l are constant terms then, inductance is directly proportional to square of number of turns.
now, according to question,
the number of turns in a coil is doubled without any change in inductance lending of the coil.
so, inductance of coil becomes four times.
hence, when the number of turns in a coil is doubled without any change in the length of the coil , its self inductance becomes four times.
Answered by
13
Answer:
4
Explanation:
directly proportional to n2
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