Physics, asked by vandanabindlish3932, 1 year ago

When the number of turns in a coil is doubled without any change in the length of the coil, its self inductance becomes(a) Four times(b)Doubled
(c) Halved(d) Unchanged

Answers

Answered by abhi178
28

answer : option (a) four times

explanation : we know, self inductance of coil or solenoid is given by

       L = μ₀n²A/l

where μ is permeability of medium, n is number of turns of a coil, A is cross sectional area of coil and l is length of coil.

if A , l are constant terms then, inductance is directly proportional to square of number of turns.

now, according to question,

   the number of turns in a coil is doubled without any change in inductance lending of the coil.

so, inductance of coil becomes four times.

hence, when the number of turns in a coil is doubled without any change in the length of the coil , its self inductance becomes four times.



Answered by sai1395381
13

Answer:

4

Explanation:

directly proportional to n2

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