When the number x is added to both the numerator and the denominator of the fraction 3/8 the result is the fraction 3/4. What is x equal to?
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If the same number is added to both the numerator and denominator of the fraction 6/9 and get a result of 2, what number is added?
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Let the number x to be added to both numerator and denominator as
=(6+x)/(9+x)
Now according to the condition this fraction is equal to 2
(6+x)/(9+x)=2 (1)
Multiplying (9+x) on both sides
(6+x)=2(9+x) (As (9+x) cancelled on the R.H.S)
6+x=18+2x (By distributive property)
subtracting 2x from both sides
6+x-2x=18+2x-2x
6-x=18
subtracting 6 from both sides
6-6-x=18-6
-x=12
Multiplying -1 on both sides
x=-12 (Answer)
Now You can check by putting back the value of x in equation (1) as
(6+x)/(9+x)=2
(6+(-12))/9+(-12)=2
(6-12)/(9-12)=2
-6/-3=2
2=2
Hence proved.
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