Question

When the object is placed at 16cm in front of a convex lens of focal length 24cm , the image is formed at_____.​

Answer 1

Answer:

It is a virtual image with image distance 48 cm.

Explanation:

f = 24 cm

u = 16 cm

=> v = ?

According to lens formula  $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ , we have to apply sign conventions for given value only  while applying in  problems.

$\frac{1}{24} = \frac{1}{v} +\frac{1}{16}$ by applying sign conventions

$\frac{1}{24} -\frac{1}{16} =\frac{1}{v}$

1/v=2-3/48

1/v=-1/48