Question

when the object is placed at distance of 50cm from concave spherical mirror the magnification produced is -0.5cm where should be the object be placed to get magnification of 0.2​

Answer 1

Magnification = image distance / object distance

The magnification in this case = - 0.5

Object distance = 50cm

-0.5 = i / 50

i = 50 × 0.5 = 25cm

To produce a magnification of - 1/5 = 0.2

Given the image distance = 25

25/o = 0.2

Where O = is the object distance

25 = 0.2O

O = 25/0.2

O = 125cm

Answer 125 cm

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Answer 2

Answer:

GIVEN:- U = 50 cm ( but we take -50 because in all cases object is placed in left side of the mirror)

Magnification = -1/2

SOLUTION :- We know that

Magnification = -v/u

-1/2= -v/-50

v = -25 cm ( here minus sigh means image is at left side of the concave mirror)

NOW , we have to calculate focal length because focal length is fixed is fixed for calculating object distance further,

WE KNOW THAT

1/f = 1/v + 1/u

by using this formula we have,

1/f = 1/-25+ (1/-50)

1/f = 1/-25 - 1/50

1/f = -3/50

NOW WE ARE CALCULATING THE OBJECT DISTANCE FOR MAGNIFICATION = -1/5

Magnification = -1/5

we also know that

Magnification = -v/u

-1/5 = -v/u

5v = u

v = u/5

FROM MIRROR FORMULA WE HAVE,

1/f = 1/v + 1/u

-3/50 = 5/u + 1/u

-3u = 50×6

u = 50×6/-3

u = - 100 cm ( here minus sigh shows that the object is placed in the left side of the mirror)

SO , THE FINAL ANSWER IS = 100 CM