Question

when the origin is shifted to the point (2,3)the transformed equation of a curve is x²+3xy-2y²+17x-7y-11=0.find the original equation of the curve.
please can anyone help me!​

Answer 1

Answer:

As origin is shifted to point (−2,3),

So, put, x=x+2 and y=y−3

⟹(x+2)

2

+2(y−3)−3=0

⟹x

2

+4x+4+2y−6−3=0

⟹x

2

+4x+2y−5=0