Question

when the original price of a toy was increased by 50% the price of one dozen drivers rupees 180 what is the original price of one time​

Answer 1

Answer:

Let original cost of each toy be 100 Rs.

Number of toy originally sold be 100

After increasing the rate by 20%

New cost = 100+(100×

100

20

)=120

Number of Toy sold =100−15=85

Therefore original sale proceeds = 100×100=10000

Therefore New sale proceeds = 120×85=10200

increase% =

10000

((10200−10000)×100)

⇒2 % increase

Hence, option 'C' is correct.

Answer 2

Step-by-step explanation:

Given Problem:-

when the original price of a toy was increased by 50% the price of one dozen drivers rupees 180 what is the original price of one time

Solution:-

Let the original price of a toy be =Rs.X

Increasing percentage in the price =50%

New price of the toy =X+50%ofX

=>X+(50X/100)

=>X+X/2

=>(2X+X)/2

=>3X/2

The new price after increased of the toy =3X/2

The price of one dozen drivers =180

=>3X/2=180

=>3X=2×180

=>3X=360

=>X=360/3

=>X=120

Answer:-

The original price of the toy =Rs.120