when the planet Jupiter is at a distance of 82 5.7 km from the earth it angular diameter is measured to be 35.7 to second of Arc calculate the diameter of Jupiter.
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Here, r=824.7×106km.
θ=35.72′′=35.7260×60×π180radian
Diameter, I = ?
As I=rθ∴I=824.7×106×35.72×π60×60×180km=1.492×105km
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