When the polynomial 2x^3-
kx^2 + (5k-3)x-8 is divided by x-2,
remainder is 14. Find the value of 'k'.
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Answer:
6 is the value
Step-by-step explanation:
Let f ( x ) = 2 x³ - k x² + 7 x - 1
If f ( x ) is divided be x - 2 ,
remainder = f ( 2 )
Hence :
f ( 2 ) = 5
⇒ 2 x³ - k x² + 7 x - 1 = 5
⇒ 2 . 2³ - k . 2² + 7 . 2 - 1 = 5
⇒ 16 - 4 k + 14 - 1 = 5
⇒ - 4 k = 5 - 13 - 16
⇒ - 4 k = - 24
⇒ k = - 24 / - 4
⇒ k = 6
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