Question

when the polynomial 2x³-3x²+ax-5 is divided by 2x-3, the remainder is 7. find the value of 'a'.​

Answer 1

Step-by-step explanation:

2x-3=0

2x=3

x =3/2

P(x)=2x^3-3x^2+ax-5

P(3/2)=2(3/2)^3-3(3/2)^2+a(3/2)-5

=9/2-27/4+a(3/2)-5

=-9/4+a(3/2)-5

=-11/4+a(3/2)

a=-17/4

Answer 2

Step-by-step explanation:

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