Math, asked by sehajbani81, 22 hours ago

when the polynomial 6x^3+17x^2+ax-8 is divided by x+2 , the remainder obtained is 4 ,find a

Answers

Answered by anitaanitarai1980
0

Answer:

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Answered by harinibharadwaj6
1

Answer:

6x^3 +17x^2 +ax-8 =4

substitute x= -2

6 (-2)^3+17 (-2)^2-2a -8 =4

-48 +68 -2a-8-4=0

8-2a=0

a=4

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