Question

When the polynomial x^3+2ax^2-5x-7 is divided by x+1 it leaves remainder R1 and when the polynomial x^3+x^2-12x+6a is divided by x-2 it leaves remainder R2.find the value of 2R1+R2=12

Answer 1

Answer:

16a-30

Step-by-step explanation:

p(x)= x³+2ax²-5x-7

then p(-1)= -1+2a+5-7

= 2a-3

g(x)= x³+x²-12x+6a

then p(2)= 8+4-24+12a

= -12+12a

2R1= 4a-6

R2= -12+12a

2R1+R2= 4a-6+12a-12-12

= 16a-18-12

= 16a-30