Question

when the polynomials x3+ 4x sq. -11x-26 and 6x3 +17 x2+ax-8 are divided by x+2 then remainders are same. find the value of x


please solve this
on pen paper please help me a humble request ​

Answer 1

Answer:

x3+4x2-11x-26=(x+2)(x2-3x-13)

6x3+17x2-8=(x+2)(6x2+7x-4)

Therefore, x2-3x-13=6x2+7x-4

x2-10x+9=0

x=1,9

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