Question

When the pressure 5 litre of n2 is doubled and its temperature is raised from 300 kelvin to 600 km in the final volume of the gas would be?

Answer 1

Let initial pressure (P1) = X atm
... Final pressure (P2) = 2X atm
V1 = 5L                                                                 
V2 = ?
​T1 = 300K                                                               
T2= 600K

Using, 

P1V1/ T1 = P2V2/T2

X*5/300 = 2X*V2/600
By calculations,

V2= 5L

Ans = 5L


#Be Brainly❤️

Answer 2

Using The general or Ideal gas equation...
P1/T1 = P2/T2

V2 = 5L