Question

When the pressure of 5L of N
2 is doubled and its temperature is raised from 300K to 600K, the volume of the gas would be:​

Answer 1

Answer:

Let the initial pressure (p1) =Xatm

The final pressure (p2) = 2Xatm

Given: V

1

= 5L

V

2

= ?

T

1

= 300K

T

2

= 600K

Now,

T

1

P

1

V

1

=

T

2

P

2

V

2

300

X×5

=

600

2X×V

2

5X=

2

2X×V

2

10X=2X xV

2

V

2

=5L