Question

When the pressure of 5L of N₂ gases doubled and its temperature is raised from 300k to 600k the final volume of N₂ in liters will be _________​

Answer 1

Answer:

final volume = 5L

Explanation:

PV=nRT

{ P(1)V(1) } ÷ { P(2)V(2) } = { n(1)RT(1) } ÷ { n(2)RT(2) }..1

given

P(2) = 2×P(1)

T(1) = 300K

T(2) = 600K

V(1) = 5L

V(2) = x ...{let}

n(1) = n(2) = n

now putting above value in equation 1

we get,

{ P(1) × 5 } ÷ { 2×P(1) × x } = {nR × 300} ÷ {nR × 600}

=> 5 / {2x} = 1/2

=> 5 × 2 / 2 = x

=> x = 5L