when the pressure of a gas contained in a closed vessel is increased by 0.4%,the temperature increases by 1 degree celsius.the initial temperature was
options are 250k,250celsius,25kelvin and 2500k
SeldonAngmo:
hey sorry can't help ya with that
Answers
Answered by
3
here it is
p1=p, t1= t, p2= p + (0.4% of p)
= p +0.4/100 ×p = p + p/250 t2= t + 1
from Gay Lussac's law
p1/p2 = t1/t2
p/ p + p/250
= t/t+1
solving n goin through the whole of it we get t= 250K
p1=p, t1= t, p2= p + (0.4% of p)
= p +0.4/100 ×p = p + p/250 t2= t + 1
from Gay Lussac's law
p1/p2 = t1/t2
p/ p + p/250
= t/t+1
solving n goin through the whole of it we get t= 250K
Similar questions