Math, asked by manasameena4, 1 month ago

When the quadratic equation 5x² = 2 ( 2x + 3 ) is expressed in the
standard form, the constant term obtained is
(A)
5
(B) 6
tej 4
(D) -6​

Answers

Answered by aryansuts01
1

Answer:

The constant is -6

If complex roots will be included, a quadratic function will always have two roots; a double root counts as two. An analogous formula can be created by factoring a quadratic formula.

step-by-step explanation:

A quadratic equation can be expressed as the following:

ax² + bx + c = 0

Quadratic equations can be solved using one of three main strategies: factoring, the polynomial formula, or filling the square.

Factoring:

  • To factor an equation with a quadratic term
  • Put the equation with all terms on one side and zero on the other.
  • Factor.
  • Each factor should be set to zero.
  • Fix each of these problems.
  • Put your solution into the original equation to make sure.

Numerous quadratic problems cannot be factored out. When the roots, or solutions, are non-rational numbers, this is typically true.

Completing the square:

  • Completion the squares is a third strategy for resolving quadratic formula that works with both real and fictitious roots.
  • Rewrite the equation as axe 2 + bx = - c.
  • Verify that an is equal to 1 (and multiply the equation by if it is not).
  • Add to the both sides of an equation to use the value of b from in this equation to create a perfect square on the left side of the equation.
  • Calculate the square roots of the equation's two sides.
  • Put the resultant equation to use.

5x^{2} =2(2x+3)\\5x^{2} =4x+6\\5x^{2} -4x-6=0

So, the constant is -6

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Answered by ushmagaur
0

Answer:

Option (D) is the correct answer.

Step-by-step explanation:

Quadratic equations:-

  • The polynomial equations of degree 2 in one variable of the type ax^2 + bx + c = 0, where a, b, c, ∈ R and a ≠ 0.

Step 1 of 1

Consider the given quadratic equation as follows:

5x² = 2(2x + 3)

Simplify as follows:

5x² = 4x + 6

Then, the standard form of the equation (1) is,

5x² + (-4)x + (-6) = 0

Here, a = 5, b = -4 and c = -6

Observe that the constant term is -6.

Thus, option (D) is the correct answer.

And,

The options (A), (B), and (C) are incorrect.

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