Question

when the radius of a cylinder is doubled in order to have no change in the volume the height will be? pls answer​

Answer 1

Answer:

NEW HEIGHT IS ONE FOURTH OF ORIGINAL HEIGHT.

Step-by-step explanation:

$( r2 )= 2 \times (r1) \\ \\ v1 = v2 \\ \\\pi {(r1)}^{2} (h1) = \pi {(r2)}^{2} (h2) \\ \\ ( {r1)}^{2} (h1) = {(r2)}^{2} (h2) \\ \\ ( {r1)}^{2} (h1) = {(2(r1))}^{2} (h2) \\ \\( h1) = 4(h2) \\ \\ h2 = \frac{h1}{4} . \\ \\ therefore \: \: height \: will \: be \: reduced \: to \: one \: fourth \: of \: the \: original \: height.$