Question

When the resistance connected in series with a cell halved the current is slightly less than double why???

Answer 1

Hi friend,

Because the Voltage given by a cell is V = e - ir

where ' r ' is internal resistance and 'e' is electromotive force and 'i' is current.

e = ir ( where 'R' is external resistance)

So, V= iR - ir

when you half R , you will get a little less than double current , because i = V / ( R - 1 ) Not V/R

this is only reason of internal resistance of cell.

.....i hope it helps you


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