When the resistance connected in series with a cell is halved, the current is slightly less than the double. Why?
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Answer. because voltage given by a cell is V = e -ir where r is internal resistance and e is electromotive force and i is current. when you half R, you will get a little less than double current because i = v/(R - r) NOT v/R.
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Because voltage given by a cell is V = e -ir where r is internal resistance and e is electromotive force and i is current. when you half R, you will get a little less than double current because i = v/(R - r) NOT v/R.
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