Math, asked by meankitz933, 5 hours ago

when the roots of a polynomial quadratic equation ax2+bx+c=0 does not exist?

Answers

Answered by Anonymous
4

Answer:

Affected quadratic equation of type ax2 + bx + c = 0, b 0. D = b2 – 4ac, is called the discriminant which decides the nature of roots. If D > 0, Roots are real and unequal. If D = 0, Roots are real and equal

Step-by-step explanation:

Answered by Anonymous
1

Answer:

Step-by-step explanation:

If a quadratic equation ax Square + bx + c = 0, where a, b, c are real numbers and a is not equal to zero, has real and equal roots then

{b}^{2} - 4ac = 0b

2

−4ac=0

If a quadratic equation ax Square + bx + c = 0, where a, b, c are real numbers and a is not equal to zero, has real and unequal roots then

{b}^{2} -4ac \geq 0b

2

−4ac≥0

If a quadratic equation ax Square + bx + c = 0, where a, b, c are real numbers and a is not equal to zero, has non-real roots then

{b}^{2} - 4ac \leq 0b

2

−4ac≤0

Step-by-step explanation:

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