when the same amount of electricity is passed through solutions of silver nitrate and copper sulphate , 0.4 grams copper is deposited. The amount of silver deposited is?
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63.5 gm copper = 2×96500C charge
0.4 gm copper = (193000/63.5)×0.4=1215.7 charge
96500 C = 107.8gm Silver
1215.7 C = (107.9/96500)×1215.7=1. 4 gm of silver
0.4 gm copper = (193000/63.5)×0.4=1215.7 charge
96500 C = 107.8gm Silver
1215.7 C = (107.9/96500)×1215.7=1. 4 gm of silver
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