Physics, asked by karthiksharmalakkara, 5 months ago

When the screw gauge is used to measure the diameter of a nail, the pitch scale reading is found to be 1.5 mm and the head scale reading is 18. The radius of the nail is
WITH FORMULA​

Answers

Answered by sanjanaguptacute
1

Explanation:

Here, pitch of the screw gauge, p=1 mm

Number of circular divisions, n=100

Thus, least count LC=p/n=1/100=0.01 mm=0.001 cm

Diameter of the wire =MSR(CSR×LC)=0+(52×0.001cm)=0.052 cm

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