When the sides of a square are increased by 4. area become 256. What is the length of a
side of the first square ?
Answers
Answered by
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Solution :-
Let :-
Side of first square = x
Side of second square = x + 4
According to the question :-
-
Side of a square cannot be negative.
So, x = 12
Side of the first square = 12 cm
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Correct Question:
- When the sides of a square are increased by 4, then the area becomes 256. What is the length of the side of the square ?
Answer:
- x = 12
Given:
- The sides of a square are increased by 4
- After the sides are increased, the area becomes 256
To find:
- Length of the side of the square
Solution:
Let the side of the square be x.
New side of the square = ( x + 4 )
We know that,
Area of a square = (Side)²
So, by substituting the values, we get :
256 = (x + 4)²
x² + 2 × x × 4 + (4)² = 256
(By using (a + b)² = a² + 2ab + b²)
x² + 8x + 16 = 256
x² + 8x = 256 - 16
x² + 8x = 240
x² + 8x - 240 = 0
Here, we have to use middle term splitting i.e.
- x² + (a + b)x + ab
So in x² + 8x - 240 = 0,
- Sum = 8
- Product = (- 240)
Now,
- Sum = 8 = 20 - 12
- Product = (- 240) = 20 × (-12)
x² + 8x - 240 = 0
x² + 20x - 12x - 240 = 0
x ( x + 20) - 12 (x + 20) = 0
(x + 20) (x - 12) = 0
(By taking ( x + 20 ) as common)
Case 1 :
x + 20 = 0
x = (-20)
Case 2 :
x - 12 = 0
x = 12
We know that length cannot be negative,
Concepts Used:
- Assumption of unknown values
- Area of a square = (Side)²
- Substitution of values
- (a + b)² = a² + 2ab + b²
- Transposition Method
- Middle Term splitting method
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