Math, asked by avenukuttan, 6 months ago

When the sides of a square are increased by 4. area become 256. What is the length of a
side of the first square ?​

Answers

Answered by Ataraxia
23

Solution :-

Let :-

Side of first square = x

Side of second square = x + 4

According to the question  :-

-\longrightarrow \sf (x+4)^2 = 256 \\\\\longrightarrow x^2+4^2+2 \times 4 \times x = 256 \\\\\longrightarrow x^2+16+8x = 256 \\\\\longrightarrow x^2+8x = 256-16 \\\\\longrightarrow x^2+8x = 240 \\\\\longrightarrow x^2+8x - 240 = 0 \\\\\longrightarrow x^2+20x- 12x-240 = 0 \\\\\longrightarrow x(x+20)-12(x+20) = 0 \\\\\longrightarrow (x+20)(x-12) = 0 \\\\\longrightarrow \bf x = -20 \ , \ x= 12

Side of a square cannot be negative.

So, x = 12

Side of the first square = 12 cm


Anonymous: Awesome !
Ataraxia: Thank uh!
Anonymous: Welcome :)
Answered by BrainlyPotter176
35

\red\bigstar Correct Question:

  • When the sides of a square are increased by 4, then the area becomes 256. What is the length of the side of the square ?

\pink\bigstarAnswer:

  • x = 12

\blue\bigstarGiven:

  • The sides of a square are increased by 4
  • After the sides are increased, the area becomes 256

\red\bigstarTo find:

  • Length of the side of the square

\pink\bigstar Solution:

Let the side of the square be x.

New side of the square = ( x + 4 )

We know that,

\starArea of a square = (Side)²

So, by substituting the values, we get :

256 = (x + 4)²

\implies x² + 2 × x × 4 + (4)² = 256

(By using (a + b)² = a² + 2ab + b²)

\implies x² + 8x + 16 = 256

\implies x² + 8x = 256 - 16

\implies x² + 8x = 240

\implies x² + 8x - 240 = 0

Here, we have to use middle term splitting i.e.

  • x² + (a + b)x + ab

So in x² + 8x - 240 = 0,

  • Sum = 8
  • Product = (- 240)

Now,

  • Sum = 8 = 20 - 12
  • Product = (- 240) = 20 × (-12)

\thereforex² + 8x - 240 = 0

\impliesx² + 20x - 12x - 240 = 0

\implies x ( x + 20) - 12 (x + 20) = 0

\implies (x + 20) (x - 12) = 0

(By taking ( x + 20 ) as common)

\star Case 1 :

x + 20 = 0

\implies x = (-20)

\star Case 2 :

x - 12 = 0

\implies x = 12

\becauseWe know that length cannot be negative,

\implies \boxed{\sf x \:= \:12 \:}

\green\bigstar Concepts Used:

  • Assumption of unknown values

  • Area of a square = (Side)²

  • Substitution of values

  • (a + b)² = a² + 2ab + b²

  • Transposition Method

  • Middle Term splitting method


Anonymous: Awesome !
avenukuttan: wow
BrainlyPotter176: Thank you!
Anonymous: You are most welcome mate ! :-)
Similar questions