Question

when the smaller of two consecutive integer is added to three times the larger integer the result is 43 find both the number

Answer 1

Answer:

1st number = 10

2nd number = 11

Step-by-step explanation:

Step 1 : Define x

Let the 1st number be x

Let the 2nd number be x + 1

Given, when the smaller of two consecutive integer is added to three times the larger integer, the number becomes 3(x + 1)

Given, their sum = 43

Step 2 : Find the value of x

x + 3(x + 1) = 43

=> x + 3x + 3 = 43

=> 4x + 3 = 43

=> 4x = 43 - 3

=> 4x = 40

=> x = $\dfrac{40}{4}$

=> x = 10

Step 3 : Find the numbers

1st number => x

=> 10

2nd number => x + 1

=> 10 + 1

=> 11

Answer 2

■ Suppose the first number be p

■ Suppose the second number be p + 1

■ Three times the larger integer

= 3(p + 1)

■ Sum = 43

■ According to the question :-

P + 3(p + 1) = 43

=> p + 3p + 3 = 43

=> 4p + 3 = 43

=> 4p = 43 - 3

=> 4p = 40

=> x = $\bf\huge\frac{40}{4}$

=> x = 10

■ Second number = p + 1

= 10 + 1

= 11