Question

when the son will be as old as father today the sum of their age's then will be 126 . when the father was as old as his son is today the sum of their age's then was 38​

Answer 1

Answer:

Let the present ages of son and his father are x and y respectively.  

The difference of their ages is- (y-x).

Hence, it will take (y-x) more years for son to reach his father's present age. After (y-x) years sum of their ages will be - (which is given 126)  

.

.  

[ x + (y-x) ] + [ y + (y-x) ] = 126

.

.  

3y-x = 126. ........ eq-1  

Similarly (y-x) before father's age was equal his son's present age. (y-x) years before sum of their age was- ( which is given 38)--  

[ x - (y-x) ] + [ y - (y-x) ] = 38

.

.

3x - y = 38................. eq-2  

by multiplying eq-2 with 3 and then adding to the eq-1  

3y - x = 126

9x - 3y = 114

--------------------

8x = 240  

x = 30

Putting x =30 to the eq-2  

Y= 52  

So son's age is 30 years and father's age is 52 years.

Step-by-step explanation: